Suppose I have a model like this one:
class Car(models.Model):
images = models.ManyToManyField(Image)
class Image(models.Model):
path = models.CharField()
type = models.CharField()
I want to expose two API views:
In list view I want to show only images that have type="thumbnail". In details view I want to show images of type="image".
This is more or less what the list should look like:
[{
"id": 1,
"images": [1, 2],
},
{
"id": 2,
"images": [3, 4],
}]
And the details view:
{
"id": 1,
"images": [5],
}
Note that different image ids are displayed depending on the view.
So far my serializer looks like this:
class CarSerializer(serializers.ModelSerializer):
images = serializers.ManyPrimaryKeyRelatedField()
class Meta:
model = Car
List api view:
class CarList(generics.ListAPIView):
model = Car
serializer_class = CarSerializer
Details api view:
class CarDetails(generics.RetrieveAPIView):
model = Car
serializer_class = CarSerializer
This of course gives me all images in list as well as in details and forces clients to make additional calls to get image type that should be displayed.
Is there any generic way to do it? I have seen django-filter examples, but it seems that its only possible to filter which objects are listed, not what related objects in listed objects are listed.
Fábio Gibson :
I don´t know if you are still looking for this answer, but maybe it helps someone else.\n\nFirst create a filter class like this:\n\nclass CarFilter(django_filters.FilterSet):\n having_image = django_filters.Filter(name=\"images\", lookup_type='in')\n\n class Meta:\n model = Car\n\n\nThen add the filter to your view:\n\nclass CarList(generics.ListAPIView):\n model = Car\n serializer_class = CarSerializer\n filter_class = CarFilter\n\n\nAnd that´s all. Add \"?having_image=1\" to your query string and Django filter should do the trick for you.\n\nHope it helps..",
2014-11-13T17:54:12
Anton :
I have found a other Stackoverflow question that has a solution that could be used here:\n\nHow can I apply a filter to a nested resource in Django REST framework?\n\n(see under the \"Solution\" headline in the question itself)",
2013-08-08T09:53:57